Malus's Law
I=Io•(cosφ)^2,
cos φ =sqrt(I/Io),
φ =19.19o
I=Io•(cosφ)^2,
cos φ =sqrt(I/Io),
φ =19.19o
The formula for Malus's law is:
I = I₀ * cos²θ
where I is the transmitted intensity, I₀ is the incident intensity, and θ is the angle between the transmission axis of the polarizing sheet and the direction of polarization of the incident light.
In this case, we are given the transmitted intensity (0.807 W/m²) and the incident intensity (0.972 W/m²), so we need to solve for θ.
Rearranging the formula, we have:
cos²θ = I / I₀
Taking the square root of both sides, we get:
cosθ = √(I / I₀)
Now, plug in the given values:
cosθ = √(0.807 / 0.972)
cosθ = 0.932
To find the angle θ, we can take the inverse cosine (arccos) of 0.932:
θ = arccos(0.932)
Using a scientific calculator, we find that θ ≈ 23.5 degrees.
Therefore, the angle that the transmission axis of the polarizing sheet makes with the horizontal is approximately 23.5 degrees.