how do you solve x^2-4/x^2-4+4 x 2x-4/x+2

Answer 1

it will be easier if you provide some parentheses so we can interpret the problem.

Answer 2

Noticing how everything matches up nicely I am sure you meant to type

( (x^2-4)/(x^2 - 4x + 4) )( (2x-4)/(x+2) )
= [(x+2)(x-2)/(x-2)^2][2(x-2)/(x+2)]
= 2 , where x ≠ ±2