amount invested at first ---- x
amount invested at 10% ---- 10000-x
solve for x ....
.08x + .10(10000-x) = 940
...
...
You invested $1 0,000 on two stocks paying 8% and 10% annual interest, respectively. At the
end of the year, the total interest fiom these investments was $940. How much was invested at
each rate?
1 answer