Question
A Brass rod 50.0 cm long expands 0.0734 cm when heated. Find the temperature change.
Answers
Linear Temperature Expansion Coefficient
α =ΔL/(L•ΔT),
for Brass α = 18.7•10^-6 K^-1,
ΔT = ΔL/(L• α) =
= 0.000734/(0.5•18.7•10^-6)=
= 78.5 K
α =ΔL/(L•ΔT),
for Brass α = 18.7•10^-6 K^-1,
ΔT = ΔL/(L• α) =
= 0.000734/(0.5•18.7•10^-6)=
= 78.5 K
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