Asked by Jessica
Simplify: ((2x^n)^2 - 1)/(2x^n-1)
where x is an integer and n is a positive interger.
where x is an integer and n is a positive interger.
Answers
Answered by
Steve
a^2-b^2 = (a+b)(a-b)
(2x^n)^2 - 1 = (2x^n - 1)(2x^n + 1)
so, dividing by (2x^n-1) leaves you with just
2x^n + 1
(2x^n)^2 - 1 = (2x^n - 1)(2x^n + 1)
so, dividing by (2x^n-1) leaves you with just
2x^n + 1
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