Question
Hey guys! really need help with this one!!!
On December 31, 1995, a house is purchased with the buyer taking out a 30-year $90,000 mortgage at 9% interest compounded monthly. The mortgage payments are made at the end of each month. Calculate:
(A) the unpaid balance of the loan on December 31,2005, just after the 120th payment.
(B) the interest that will be paid during January 2006.
Thanks in advance!
On December 31, 1995, a house is purchased with the buyer taking out a 30-year $90,000 mortgage at 9% interest compounded monthly. The mortgage payments are made at the end of each month. Calculate:
(A) the unpaid balance of the loan on December 31,2005, just after the 120th payment.
(B) the interest that will be paid during January 2006.
Thanks in advance!
Answers
first you need the monthly payment
PV = 90000
i = .09/12 = .0075
n = 12x30 = 360
90000 = Payment [ 1 - 1.0075^-360]/.0075
payment = 724.16
balance right after 120th payment
= 90000(1.0075)^120 - 724.16( 1.0075^120 - 1)/.0075
= 80486.77
interest on next month = 80486.77(.0075) = 603.65
PV = 90000
i = .09/12 = .0075
n = 12x30 = 360
90000 = Payment [ 1 - 1.0075^-360]/.0075
payment = 724.16
balance right after 120th payment
= 90000(1.0075)^120 - 724.16( 1.0075^120 - 1)/.0075
= 80486.77
interest on next month = 80486.77(.0075) = 603.65
Related Questions
The new york times reported that subway ridership declined after a fare increase: " There were nearl...
on january 1, 1996 a company paid for auto insurance. the insurance term began on january 1, 1995 an...
Mr. and Mrs. Boyce bought a house for $96,000 in 1995. Real estate values in their area increase app...
A house was purchased for $140,000. Three years later, the value of the house was $155,000. If the v...