A neutral solution has H3O^+ = OH^- so if the pH = 6.62 then the pOH 6.62
pH = 6.62 = -log(H3O^+).
Solve for (H3O^+)
What is the [H3O+] for a neutral solution at 50 degrees celsius?
I know that kw=[H3O+][OH-] but I am not sure what to do to get the H3O. The value I have for kw=5.76e-14 and I have the pH 6.62 but I do not know what the OH would be.
3 answers
so I would take the - log of 6.62?
I don't know if I put this in my calculator correctly but I got -0.82.