Asked by sugin
a net horizontal force of 7000N is applied to a car which is at rest.the weight of the car is 90000N. what will be the speed of the car after 10 second?
Answers
Answered by
Elena
P=mg, m=P/g
F=ma =Pa/g
a=Fg/P= 7000•9.8/90000 = 0.762 m/s^2
v=at=0.762•10=7.62 m/s
F=ma =Pa/g
a=Fg/P= 7000•9.8/90000 = 0.762 m/s^2
v=at=0.762•10=7.62 m/s
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