Question
In a 25 degree C room, hot coffee in a vacuum flask cools from 72 degree C to 54 degree in 8 hours.Find its temperature after another 8 hours.
Answers
Assume an exponential rate of decay.
T = To + (To - Ta)*ext(-kt)
where t is the time in hours. You could solve for k, but there is an easier way to do it.
In 8 hours, the initial 47 degrees above ambient temperature becomes 19 C. 40.4% of the in initial temperature difference remains after eight hours. In another 8 hours, that difference from ambient (Ta) will decrease to 0.404 * 19 = 7.7 degrees, or 32.7 degrees.
T = To + (To - Ta)*ext(-kt)
where t is the time in hours. You could solve for k, but there is an easier way to do it.
In 8 hours, the initial 47 degrees above ambient temperature becomes 19 C. 40.4% of the in initial temperature difference remains after eight hours. In another 8 hours, that difference from ambient (Ta) will decrease to 0.404 * 19 = 7.7 degrees, or 32.7 degrees.
its telling me this is wrong
Related Questions
Using the exact trigonometric ratios of 45 degree,30 degree and 60 degree,evaluate the following,lea...
Ice at 0 degree celcuis is added to 200g of water initially at 70 degree celcuis in a vacuum flask.W...
Identify the combination of angle measures that could form a triangle.(1 point) Responses 30° , 75°...