Asked by becky
                Multiply
(7-2x^4)^2
Is this right?
36(-2x^4+7)
            
        (7-2x^4)^2
Is this right?
36(-2x^4+7)
Answers
                    Answered by
            DanH
            
    woops.  this one, if I'm seeing it right...
you would have (7-2x^4)(7-2x^4), and then you have to use the "FOIL" method...right?
    
you would have (7-2x^4)(7-2x^4), and then you have to use the "FOIL" method...right?
                    Answered by
            becky
            
    So, would the answer be
-2x^4+7^2
    
-2x^4+7^2
                    Answered by
            DanH
            
    (7-2x^4)(7-2x^4)
first, multiply the first two: 7x7=49
then, multiply the outside two:7 x -2x^4, which is -14x^4.
then, multiply the inside two, which is also -14x^4
then, multiply the last two:
(-2x^4) x (-2x^4) which is 4x^8.
so, we have: 49 -14x^4 -14x^4 + 4x^8.
simplified to 49 -28x^4 + 4x^8.
    
first, multiply the first two: 7x7=49
then, multiply the outside two:7 x -2x^4, which is -14x^4.
then, multiply the inside two, which is also -14x^4
then, multiply the last two:
(-2x^4) x (-2x^4) which is 4x^8.
so, we have: 49 -14x^4 -14x^4 + 4x^8.
simplified to 49 -28x^4 + 4x^8.
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