Question

Four people sit in a car. The masses of the people are 41 kg, 47 kg, 53 kg, and 55 kg. The car's mass is 1020 kg. When the car drives over a bump, its springs cause an oscillation with a frequency of 1.00 Hz. What would the frequency be if only the 41-kg person were present?
Hz

I really don't know how to do this, and I can't even make an assumption! Help please!

Answer 1

M=41+47+53+55 = 196 kg
f=sqrt(k/M)/ 2•π
k =(2•π •f)^2•M =7.74•10^3 N/m
f1 =sqrt(k/m)/ = sqrt(7.74•10^3/41)/ 2•π =2.19 Hz.

Answer 2

Thank you, but I tried this answer its wrong and I don't know why!

Answer 3

Thanks, for the help Elena. For me this answer is also not working its saying that its wrong. :/

Answer 4

add the mass of the vehicle...