Asked by XOCHIL
solve this system of equations and solve for triple pair:
x+y+z=8
2y+4y+2z=26
-x+8y-3z=26
x+y+z=8
2y+4y+2z=26
-x+8y-3z=26
Answers
Answered by
Reiny
I think your second equation is probably
2x+4y+2z=26
add the first and third ---> 9y - 2z = 34 (#1)
multiply third by 2
-2x + 16y - 6z = 52
add that to the second
20y -4z = 78
10y - 2z = 39 (#2)
#2 - #1 : ----> y = 5
sub into #1
45 - 2z = 34
-2z = -11
z = 5.5
back into the first
x + 5 + 5.5 = 8
x = -2.5
x = -2.5
y= 5
z = 5.5
2x+4y+2z=26
add the first and third ---> 9y - 2z = 34 (#1)
multiply third by 2
-2x + 16y - 6z = 52
add that to the second
20y -4z = 78
10y - 2z = 39 (#2)
#2 - #1 : ----> y = 5
sub into #1
45 - 2z = 34
-2z = -11
z = 5.5
back into the first
x + 5 + 5.5 = 8
x = -2.5
x = -2.5
y= 5
z = 5.5
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