Asked by felicia
the perimeter of a rectangle is 182 inches the length exceeds the width by 59 inches find the length and the width
Answers
Answered by
Ms. Sue
P = 2L + 2W
182 = 2(W + 59) + 2W
182 = 4W + 118
182 - 118 = 4W
64 = 4W
16 = W
182 = 2(W + 59) + 2W
182 = 4W + 118
182 - 118 = 4W
64 = 4W
16 = W
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