just recall that x=rcosθ y=rsinθ
you have r=3, θ=4π/3
x = 6cos4π/3 = 6*(-1/2) = -3
y = 6sin4π/3 = 6*(-√3/2) = -3√3
What is the answer and how did you do for this question? Please I really need help! :(
Express in rectangular form:
6(cos(4π)/(3)+i sin(4π)/(3)?
1 answer
1 answer