Asked by Maggie
Each of the four wheels of a car push on the road with a force of 4.0*10^3 N [down]. The driving force on the car is 8.0*10^3 N [W]. The fictional resistance on the car is 6.0*10^3 [E]. Calculate the following
A) the mass of the car
B) the net force on the car
C) the cars acceleration
The answers are
A) 1.6*10^3 kg
B) 2.0*10^3 N [W]
C) 1.2m/s^2
I just don't understand how to get these correct answers
A) the mass of the car
B) the net force on the car
C) the cars acceleration
The answers are
A) 1.6*10^3 kg
B) 2.0*10^3 N [W]
C) 1.2m/s^2
I just don't understand how to get these correct answers
Answers
Answered by
Elena
M•g =4•m•g= 4•4•10^3 N
M = 4•4•10^3/9.8 =1.63•10^3 kg
There are 4 forces: Mg (downwards), normal force N ( upwards), driving force(to the left), and resistance force (to the right) . Net force is their sum.
Since N=Mg, net force is 8•10^3 – 6•10^3 = 2•10^3 N (to the left).
Acceleration = net force/mass =2•10^3/1.63•10^3 = 1.23 m/s^2
M = 4•4•10^3/9.8 =1.63•10^3 kg
There are 4 forces: Mg (downwards), normal force N ( upwards), driving force(to the left), and resistance force (to the right) . Net force is their sum.
Since N=Mg, net force is 8•10^3 – 6•10^3 = 2•10^3 N (to the left).
Acceleration = net force/mass =2•10^3/1.63•10^3 = 1.23 m/s^2
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