Asked by Yoona

The three pigls are building their houses while the brik=ck house building pig and the stick house building pig are working at a steady rate, the straw house building pig(knowing the wolf will arrive first at his house) is frantically increasing his rate of building by 2feet/minute. the straw house building pig has to make his house 16 ft tall(right now, it's 0 feet tall) and the wolf is scheduled to arrive in 5 minutes. Will the pig have his house built for the wolf to blow down by the time he arrives?

Answers

Answered by naseba
are you sure this is a question?
Answered by Steve
this is just a standard acceleration problem.

s = 1/2 at^2
16 = 1/2 * 2 * t^2
16=t^2
t=4

so, in 4 min the house will be 16' tall, and he will be (briefly) safe.
Answered by Steve
now, if you want to use your calculus, let f(t) be the height of the house after t minutes.

f ''(t) = 2

f '(t) = 2t + c
f '(0) = 0 means c=0 and
f '(t) = 2t

f(t) = t^2+c
f(0) = 0 means c=0, so
f(t) = t^2

16 = t^2
t=4
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