Question

What happens to the concentration of HI(g) when the total pressure on the equilibrium reaction
2HCl(g) + I2(s) <--> 2HI(g) + Cl2(g)
is increased (by compression)?
1. increases
2. Unable to determine
3. decreases
4. remains the same

Answer 1

For an increase in pressure the reaction shifts to the side with the fewer mols. In this reaction the number of mol gas is the same on both side; therefore, there will be no shift due to pressure changes.

Answer 2

I meant to take out number 4 because it was an incorrect answer, I just don't understand why.

Answer 3

I just reread the question and my answer is wrong. Give me a second.

Answer 4

2HCl(g) + I2(s) <--> 2HI(g) + Cl2(g)

I tried to delete my first response before you read it but I didn't make it so I put in the oops message. Here is the scoop. (I was alerted by another of your questions below.)
My initial statement concerning pressure changes is correct; i.e., an increase in pressure will shift the reaction to the side with the fewer mols gas (NOTE gas). In this reaction, you have 3 mols gas on the right and only two mols gas on the left (note that I2 is a solid and not a gas); therefore, the reaction will shift to the left which will decrease the concn of HI.

Answer 5

It decreases

Answer 6

What happens to the concentration of NO(g) when the total pressure on the equilibrium reaction 3NO2(g) + H2O(l) = 2 HNO3(aq) + NO(g)

Answer 7

What happens to the concentration of NO(g) when the total pressure on the equilibrium reaction 3NO2(g) + H2O(l) = 2 HNO3(aq) + NO(g) is increased by compression