Question

An object 3.28 cm tall is placed 10.5 cm in front of a mirror, which creates an upright image rant is 6.43 cm in height.
A. What is the magnification of the image?
B. What is the radius of the curvature of the mirror?
A. Mag. = 6.43/3.28 = 1.96

B. R = 2 f

Get the focal length f from the equation

1/do + 1/di = 1/f

do = object distance = 10.5 cm
di = image distance = 20.6 cm
How did you get 20.6?

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