Asked by polygon
each interior angle of a regular polygon is 18 degree more than eight times an exterior angle. the number os sides of polygon is.
Answers
Answered by
Steve
at each vertex, interior + exterior = 180 degrees.
If exterior = x,
x+(8x+18) = 180
9x = 162
x = 18
he exterior angle of a regular n-gon is 360/n, so
18 = 360/n
n = 20
If exterior = x,
x+(8x+18) = 180
9x = 162
x = 18
he exterior angle of a regular n-gon is 360/n, so
18 = 360/n
n = 20
Answered by
drwls
Interior angle = 180 - (exterior angle) = 180 -360/N
Exterior angle = 360/N
180 - (360/N) = [8*360/N] +18
9*360/N = 162
N = 20 sides
It is called an icosagon
Exterior angle = 360/N
180 - (360/N) = [8*360/N] +18
9*360/N = 162
N = 20 sides
It is called an icosagon
Answered by
Anonymous
(2n-4)/n×90
= 8×4×90/n+18
=(2n-4)/n×5= 160/n+1
= 10= n-20=60+n
=10n-n=180
9n=180
n=20
= 8×4×90/n+18
=(2n-4)/n×5= 160/n+1
= 10= n-20=60+n
=10n-n=180
9n=180
n=20
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