Asked by Anonymous
LAB
STUDENT is asked to determine the heat of neutralization for H + OH --> H2O by combining 1 M NaOH and 1 M HCl in an open styrofoam calorimeter.
Assume
1. solutions are same temp at start
2. densities of solutions are the same as h20
3. specific heat capacity of the combined solutions equals that of water
4. heat lost to air is negligible.
explain how to calculate the number of moles of water formed during the experiment
STUDENT is asked to determine the heat of neutralization for H + OH --> H2O by combining 1 M NaOH and 1 M HCl in an open styrofoam calorimeter.
Assume
1. solutions are same temp at start
2. densities of solutions are the same as h20
3. specific heat capacity of the combined solutions equals that of water
4. heat lost to air is negligible.
explain how to calculate the number of moles of water formed during the experiment
Answers
Answered by
drbob222
NaOH + HCl ==> H2O + NaCl
What volume of NaOH? L x M = mols
What volume of HCl? It had to be the same as the volume of NaOH if both solutions were 1 M exactly. Then L x M = mols.
x mols NaOH + x mols HCl MUST form x mols H2O, whatever x is.
What volume of NaOH? L x M = mols
What volume of HCl? It had to be the same as the volume of NaOH if both solutions were 1 M exactly. Then L x M = mols.
x mols NaOH + x mols HCl MUST form x mols H2O, whatever x is.
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