Asked by Anne

A loud speaker of mass 24.0 kg is suspended a distance of h = 2.00 m below the ceiling by two cables that make equal angles with the ceiling. Each cable has a length of 3.50 m. What is the tension in each of the cables?
Answered by bobpursley
Each cable holds one half the weight.

verticalforceleft=verticalforceright=24g/2*cosTheta*tension

but CosTheta=2/3.5

solve for tension

Answered by Anne
Thanks! I did get this far, but it didn't seem right!
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