Question
(1/tanx-secx))+(1/(tanx+secx))=-2tanx
Answers
olivia
i've already attempted this question but something went wrong...
Steve
1/(tan-sec) + 1/(tan+sec)
= [(tan+sec)+(tan-sec)] / (tan^2 - sec^2)
= 2tan/(-1)
= -2tan
= [(tan+sec)+(tan-sec)] / (tan^2 - sec^2)
= 2tan/(-1)
= -2tan