Asked by olivia

(1/tanx-secx))+(1/(tanx+secx))=-2tanx

13 years ago

Answered by olivia

i've already attempted this question but something went wrong...

13 years ago

Answered by Steve

1/(tan-sec) + 1/(tan+sec)
= [(tan+sec)+(tan-sec)] / (tan^2 - sec^2)
= 2tan/(-1)
= -2tan

13 years ago

There are no AI answers yet. The ability to request AI answers is coming soon!

Submit Your Answer

We prioritize human answers over AI answers.

If you are human, and you can answer this question, please submit your answer.