Asked by olivia

(1/tanx-secx))+(1/(tanx+secx))=-2tanx

Answers

Answered by olivia
i've already attempted this question but something went wrong...
Answered by Steve
1/(tan-sec) + 1/(tan+sec)
= [(tan+sec)+(tan-sec)] / (tan^2 - sec^2)
= 2tan/(-1)
= -2tan
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