Question

Mark made a business trip of 290 miles. He averaged 56 mph for the first part of the trip and 60 mph for the second part. If the trip took 5 hours, how long did he travel at each rate?
Reiny
time for first trip --- x hrs
time for 2nd part of trip ---- (5-x)

distance for 1st part = 56x miles
distance for 2nd part = 60(5-x)

so solve:
56x + 60(x-5) = 290