use the Ksp of SnS2= 1.0X10^-70 and calculate the pH of a hydrogen sulfide solution needed to precipitate 99.99% of the tin(IV) ion assuming [Sn^4+]=0.05M and that [H2S]=0.10M.

Answer 1

I have two problems with this. First, tin(IV) sulfide is SnS2 without the double minus charge; second, my references show SnS2 Ksp as 1E-46

Answer 2

well that's the ksp they gave in the question