Question
A 60kg front seat passenger in a car moving initially with a speed of 18m/s (40 MPH) is brought to rest by an air bag in a time of 0.4s
a. What is the impulse acting on the passenger?
b.What is the average force acting on the passenger in this process?
a. What is the impulse acting on the passenger?
b.What is the average force acting on the passenger in this process?
Answers
40 Miles/hr is actually 17.88 m/s, not 18, but let's say it's 18.
The initial momentum, is 60*18 = 1080 kg m/s.
That equals the impulse and the momentum change hen stopping.
Divide the impulse by the time (in seconds) for the average force, in newtons.
Fav = 1080/0.4 = ___ N
The initial momentum, is 60*18 = 1080 kg m/s.
That equals the impulse and the momentum change hen stopping.
Divide the impulse by the time (in seconds) for the average force, in newtons.
Fav = 1080/0.4 = ___ N
2700
Related Questions
A passenger in the rear seat of a car moving at a steady speed is at rest relative to
the side of...
A 54.5-kg passenger in the back seat of a van
is wearing a seat belt when the van runs into
a ston...
A 60-kg front seat passenger is moving in a car initially with a speed of 18.4 m/s is brought to res...
A car moving at 12m/s crashes into a tree and stops in 26ms. Calculate the force the seat belt exert...