Asked by Karien
A 60kg front seat passenger in a car moving initially with a speed of 18m/s (40 MPH) is brought to rest by an air bag in a time of 0.4s
a. What is the impulse acting on the passenger?
b.What is the average force acting on the passenger in this process?
a. What is the impulse acting on the passenger?
b.What is the average force acting on the passenger in this process?
Answers
Answered by
drwls
40 Miles/hr is actually 17.88 m/s, not 18, but let's say it's 18.
The initial momentum, is 60*18 = 1080 kg m/s.
That equals the impulse and the momentum change hen stopping.
Divide the impulse by the time (in seconds) for the average force, in newtons.
Fav = 1080/0.4 = ___ N
The initial momentum, is 60*18 = 1080 kg m/s.
That equals the impulse and the momentum change hen stopping.
Divide the impulse by the time (in seconds) for the average force, in newtons.
Fav = 1080/0.4 = ___ N
Answered by
Alex
2700
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