Asked by srihita
Bob's age is 38 and his son"s age is 4. In how many years' time will Bob's age be twicethe age of his son?
Answers
Answered by
xavier
38+x = 2(4+x)
38+x = 8 +2x
38-8 = 2x - x
30 = x
So, His age is 30+38 = 68
His son age is 30 + 4 = 34
difference is 68-34 = 30
38+x = 8 +2x
38-8 = 2x - x
30 = x
So, His age is 30+38 = 68
His son age is 30 + 4 = 34
difference is 68-34 = 30
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