Asked by lisa
a player uses a hockey stick to increase the speed of a 0.200 kg hockey puck by 6 m/s in 2 seconds.
how much force was exerted on the puck?
how much force did the puck exert on the hockey stick?
how much force was exerted on the puck?
how much force did the puck exert on the hockey stick?
Answers
Answered by
Damon
Force = rate of change of momentum (in other words m (delta v/ delta t) or m a)
F = m (change in velocity/change in time)
F = .2 (6/2) = .6 Newtons average during the 2 seconds.
Another way, which is really the same, is to say Force * time = impulse which is mass times change in velocity
F * 2 = .2 (6)
F = .6 Newtons again
Newton's third law says same force, .6 Newtons exerted back on the stick by the puck
F = m (change in velocity/change in time)
F = .2 (6/2) = .6 Newtons average during the 2 seconds.
Another way, which is really the same, is to say Force * time = impulse which is mass times change in velocity
F * 2 = .2 (6)
F = .6 Newtons again
Newton's third law says same force, .6 Newtons exerted back on the stick by the puck
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