Asked by sherry
Solve using the substitution method.
0.3x+0.2y=5,0.5x+0.4y=11
0.3x+0.2y=5,0.5x+0.4y=11
Answers
Answered by
Reiny
I would multiply each equation by 10 to get rid of those decimals
3x + 2y = 50 ---> 2y = 50-3x
5x + 4y = 110
sub 2y= 50-3x into the 2nd
5x + 2(50-3x) = 110
5x + 100 - 6x = 110
-x = 10
x = -10
into 2y = 50-3x = 50-3(-10)
2y = 80
y = 40
x = -10, y = 40
3x + 2y = 50 ---> 2y = 50-3x
5x + 4y = 110
sub 2y= 50-3x into the 2nd
5x + 2(50-3x) = 110
5x + 100 - 6x = 110
-x = 10
x = -10
into 2y = 50-3x = 50-3(-10)
2y = 80
y = 40
x = -10, y = 40
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