how much heat energy is released from cooling 35 grams of steam at 135 degrees celcius down to freezing it to negative 45 degrees celcius?

Answer 1

Note the correct spelling of celsius.

There are two equations you need to do this.
Within a phase use
mass x specific heat x (Tfinal-Tinitial)
For example to change T of water from liquid water at 100 C to liquid water at 0 C, it is
mass H2O x 4.184 x (0-100) = ?

At a phase change use
mass x heat fusion at freezing point
mass x heat vaporization at boiling point.
For example, to convert steam at 100 C to liquid at 100 C it will be
mass steam x heat vaporization.

Then add each part to find the total heat transferred.