Asked by Holly
A 80- kg child sits in a swing suspended with 2.6- m-long ropes. The swing is held aside so that the ropes make an angle of 46 o with the vertical. Use conservation of energy to determine the speed the child will have at the bottom of the arc when she is let go.
Answers
Answered by
drwls
(M/2)Vmax^2 = M g L(1 - cos46)
L(1- cos 46) is the maximum rise of the swing above the bottom position, where the velocity is Vmax
Vmax = sqrt[2 g L (1-cos46)]
L(1- cos 46) is the maximum rise of the swing above the bottom position, where the velocity is Vmax
Vmax = sqrt[2 g L (1-cos46)]
Answered by
Holly
does 1-cos46 represent L or is L part of that equation?
Answered by
drwls
L is the rope length, and is part of the equation. I already told you what
L*(1- cos 46) is .
L*(1- cos 46) is .
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