Question

2 moles of an ideal gas at 20k changes from a pressure of 15 atm to 3 atm at constant temperature. Calculate the work done by the gas.
At constant temperature, P*V = constant and
P dV = - V dP = -nRT/P*dP

Work done is therefore
Integral P dV = -(nRT) dP/P
= (-nRT) ln P2/P1
= nRT*ln(P1/P2)
= 2.0 moles*RT*ln5

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