Asked by maria
A large water tank has an inlet pipe and an outlet pipe. The inlet pipe has a diameter of 2.19 cm and is 1.25 m above the bottom of the tank. The outlet pipe has a diameter of 5.93 cm and is 4.85 m above the bottom of the tank. A volume of 0.411 m^3 of water enters the tank every minute at a gauge pressure of 1 atm.
a) What is the velocity of the water in the outlet pipe?
b) What is the gauge pressure in the outlet pipe?
a) What is the velocity of the water in the outlet pipe?
b) What is the gauge pressure in the outlet pipe?
Answers
Answered by
drwls
It seems that water is being pumped into an opening near the bottom of the tank and being removed from an outlet higher above. Is this supposed to be a steady state situation?
If so,
(a) V*(outlet pipe area)= (volume flow rate at inlet)
(b) The guage pressure difference is (rho)*g*h
where h is the difference of heights of inlet and outlet
If so,
(a) V*(outlet pipe area)= (volume flow rate at inlet)
(b) The guage pressure difference is (rho)*g*h
where h is the difference of heights of inlet and outlet
Answered by
Anonymous
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