Asked by Help
A buoy oscillates in simple harmonic motion according to the motion of waves at sea. An observer notes that the buoy moves a total of 6 feet from its lowest point to its highest point. The buoy returns to its highest point every 15 seconds.
Amplitude: 6 feet
Period: ???
Frequency: ???
Possible equation:???
Amplitude: 6 feet
Period: ???
Frequency: ???
Possible equation:???
Answers
Answered by
David
Period = time per cycle = 15 seconds
frequency = 1 / period = 1/15 hz
amplitude= 3 ft because its actually the distance from the center to each side.
from there just put it into standard form.
frequency = 1 / period = 1/15 hz
amplitude= 3 ft because its actually the distance from the center to each side.
from there just put it into standard form.
Answered by
Help
Would I use cosine or sine?
Answered by
David
It doesn't make a difference as long as your value for when t = 0 is correct since sin is just cosine phase shifted by pi/2.
Cosine is probably easier in this case because then you wont need to do a shift.
Cosine is probably easier in this case because then you wont need to do a shift.
Answered by
David
nevermind I thought it said that it began at its highest point.
Since they didn't specify any initial conditions you're free to use either sin or cosine with no phase shift.
Since they didn't specify any initial conditions you're free to use either sin or cosine with no phase shift.
Answered by
Help
How do I find omega (ω)?
Answered by
David
w = 2*pi*period
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