First, calculate the number of moles of sodium hydroxide solution:
Moles = Volume (dm^3) x Concentration (mol•dm^-3)
= 70.0 cm^3 x 0.180 mol•dm^-3
= 12.6 mol
Since the reaction between sodium hydroxide and sulfuric acid is 1:2, the number of moles of sulfuric acid solution is twice the number of moles of sodium hydroxide solution:
Moles of sulfuric acid solution = 2 x Moles of sodium hydroxide solution
= 2 x 12.6 mol
= 25.2 mol
Next, calculate the concentration of the sulfuric acid solution:
Concentration = Moles / Volume (dm^3)
We are given the volume of the sulfuric acid solution as 30.0 cm^3, so we need to convert it to dm^3:
Volume (dm^3) = 30.0 cm^3 / (1000 cm^3/dm^3)
= 0.030 dm^3
Now, calculate the concentration:
Concentration = 25.2 mol / 0.030 dm^3
= 840 mol•dm^-3
Therefore, the concentration of the sulfuric acid solution is 840 mol•dm^-3.
70,0 cm^3 of a sodium hydroxide solution ( concentration = 0,180 mol•dm^-3 ) reacts completely with 30, 0 cm^3 of a sulfuric acid solution. Calculate the concentration of the sulfuric acid solution.
5 answers
I don't believe it Bot.
Apologies for any confusion. Let's go through the calculations again.
First, calculate the number of moles of sodium hydroxide solution:
Moles = Volume (dm^3) x Concentration (mol•dm^-3)
= 70.0 cm^3 x 0.180 mol•dm^-3
= 12.6 mol
Since the reaction between sodium hydroxide and sulfuric acid is 1:2, the number of moles of sulfuric acid solution is twice the number of moles of sodium hydroxide solution:
Moles of sulfuric acid solution = 2 x Moles of sodium hydroxide solution
= 2 x 12.6 mol
= 25.2 mol
Next, calculate the concentration of the sulfuric acid solution:
Concentration = Moles / Volume (dm^3)
We are given the volume of the sulfuric acid solution as 30.0 cm^3, so we need to convert it to dm^3:
Volume (dm^3) = 30.0 cm^3 / (1000 cm^3/dm^3)
= 0.030 dm^3
Now, calculate the concentration:
Concentration = 25.2 mol / 0.030 dm^3
= 840 mol•dm^-3
Therefore, the concentration of the sulfuric acid solution is 840 mol•dm^-3.
First, calculate the number of moles of sodium hydroxide solution:
Moles = Volume (dm^3) x Concentration (mol•dm^-3)
= 70.0 cm^3 x 0.180 mol•dm^-3
= 12.6 mol
Since the reaction between sodium hydroxide and sulfuric acid is 1:2, the number of moles of sulfuric acid solution is twice the number of moles of sodium hydroxide solution:
Moles of sulfuric acid solution = 2 x Moles of sodium hydroxide solution
= 2 x 12.6 mol
= 25.2 mol
Next, calculate the concentration of the sulfuric acid solution:
Concentration = Moles / Volume (dm^3)
We are given the volume of the sulfuric acid solution as 30.0 cm^3, so we need to convert it to dm^3:
Volume (dm^3) = 30.0 cm^3 / (1000 cm^3/dm^3)
= 0.030 dm^3
Now, calculate the concentration:
Concentration = 25.2 mol / 0.030 dm^3
= 840 mol•dm^-3
Therefore, the concentration of the sulfuric acid solution is 840 mol•dm^-3.
Here is the correct solution.
moles NaOH = M x L = 0.180 x 0.070 = 0.0126
2NaOH + H2SO4 ==> Na2SO4 + 2H2O
Convert moles NaOH to mols H2SO4 this way.
0.0126 mols NaOH x (1 mol H2SO4/2 moles NaOH) = 0.0063
Then M H2SO4 = mols/L = 0.0063 mols/0.030 L = 0.21 M = 0.21 mols/dm^3
moles NaOH = M x L = 0.180 x 0.070 = 0.0126
2NaOH + H2SO4 ==> Na2SO4 + 2H2O
Convert moles NaOH to mols H2SO4 this way.
0.0126 mols NaOH x (1 mol H2SO4/2 moles NaOH) = 0.0063
Then M H2SO4 = mols/L = 0.0063 mols/0.030 L = 0.21 M = 0.21 mols/dm^3
Apologies for the previous incorrect response. Thank you for providing the correct solution.
The correct concentration of the sulfuric acid solution is 0.21 mol/dm^3.
The correct concentration of the sulfuric acid solution is 0.21 mol/dm^3.
2 answers