To find the leftover fraction after dividing \( \frac{7}{3} \) by \( \frac{2}{3} \):
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Perform the division: \[ \frac{7}{3} \div \frac{2}{3} = \frac{7}{3} \times \frac{3}{2} = \frac{7 \times 3}{3 \times 2} = \frac{21}{6} = \frac{7}{2} = 3 \frac{1}{2} \]
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Interpret the result: From the calculation, \( \frac{7}{2} \) is equal to \( 3 \) whole groups and \( \frac{1}{2} \).
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Finding the leftover part: Since you indicated that your result is "3 whole groups and 1 fractional part," it seems you're looking for what fraction remains after taking the whole number.
In terms of your question about left over after grouping, when you have:
- 3 whole groups: this accounts for \( 3 \)
- Fractional part: since you calculated it was \( \frac{1}{2} \), not \( \frac{1}{3} \) or \( \frac{2}{3} \).
Thus, you have:
\[ \text{I have } \frac{1}{2} \text{ of a group left over.} \]
So you would fill in the blank with \( \frac{1}{2} \).