Let's go through each question one by one.
Question 7: Janelle wants to sell headbands for $4 each and bracelets for $2 each, aiming to make more than $200 while selling no more than 100 items.
- Let \( b \) be the number of bracelets and \( h \) be the number of headbands.
- The total income from selling bracelets and headbands is \( 2b + 4h \).
- The total number of items sold is \( b + h \).
The conditions to satisfy are:
- \( 2b + 4h > 200 \)
- \( b + h \leq 100 \)
Now, let's check each option.
A) \( b = 20, h = 60 \):
- Total income: \( 2(20) + 4(60) = 40 + 240 = 280 > 200 \)
- Total items: \( 20 + 60 = 80 \leq 100 \) ✔️
B) \( b = 70, h = 40 \):
- Total income: \( 2(70) + 4(40) = 140 + 160 = 300 > 200 \)
- Total items: \( 70 + 40 = 110 > 100 \) ❌
C) \( b = 45, h = 60 \):
- Total income: \( 2(45) + 4(60) = 90 + 240 = 330 > 200 \)
- Total items: \( 45 + 60 = 105 > 100 \) ❌
D) \( b = 50, h = 10 \):
- Total income: \( 2(50) + 4(10) = 100 + 40 = 140 < 200 \) ❌
The only option that satisfies both conditions is A) 20 bracelets and 60 headbands.
Question 8: To find the slope \( m \) between points \( (−10, −1) \) and \( (5, −4) \): \[ m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{-4 - (-1)}{5 - (-10)} = \frac{-4 + 1}{5 + 10} = \frac{-3}{15} = -\frac{1}{5} \]
Thus, the slope is C) −1/5.
Question 9: The slope \( m \) between points \( (g, -1) \) and \( (2, 5) \) is given as \( \frac{3}{2} \): \[ m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{5 - (-1)}{2 - g} = \frac{6}{2 - g} \]
Setting the slopes equal to each other: \[ \frac{6}{2 - g} = \frac{3}{2} \]
Cross multiplying gives: \[ 6 \cdot 2 = 3(2 - g) \] \[ 12 = 6 - 3g \] \[ 12 - 6 = -3g \] \[ 6 = -3g \implies g = -2 \]
So the value of \( g \) is C) -2.
In summary: 7) A 8) C 9) C