7. Find the slope of a line that is parallel tot he line containing the points (3,4) and (2,6).
A. m=1
B. m=2
C. m= -2
D. m= 1/2
7. Find the slope of a line that is parallel tot he line containing the points (3,4) and (2,6).
4 answers
We can use the formula for slope:
m = (y2 - y1)/(x2 - x1)
where (x1,y1) = (3,4) and (x2,y2) = (2,6).
m = (6 - 4)/(2 - 3) = -2
So the slope of the line passing through (3,4) and (2,6) is -2.
Since we want a line that is parallel to this line, it must have the same slope of -2.
Therefore, the answer is C. m = -2.
m = (y2 - y1)/(x2 - x1)
where (x1,y1) = (3,4) and (x2,y2) = (2,6).
m = (6 - 4)/(2 - 3) = -2
So the slope of the line passing through (3,4) and (2,6) is -2.
Since we want a line that is parallel to this line, it must have the same slope of -2.
Therefore, the answer is C. m = -2.
8. Find the slope of a line that is perpendicular to the line containing the points ( -2, -1) and (2, -3)
A. m= -2
B. m= 2
C. m= -1/2
D. m= -1
A. m= -2
B. m= 2
C. m= -1/2
D. m= -1
We can use the formula for slope:
m = (y2 - y1)/(x2 - x1)
where (x1,y1) = (-2,-1) and (x2,y2) = (2,-3).
m = (-3 - (-1))/(2 - (-2)) = -2/2 = -1
So the slope of the line passing through these points is -1.
To find the slope of a line that is perpendicular to this line, we use the fact that the product of the slopes of two perpendicular lines is -1. So the slope of the perpendicular line is the negative reciprocal of -1, which is 1.
Therefore, the answer is B. m = 2.
m = (y2 - y1)/(x2 - x1)
where (x1,y1) = (-2,-1) and (x2,y2) = (2,-3).
m = (-3 - (-1))/(2 - (-2)) = -2/2 = -1
So the slope of the line passing through these points is -1.
To find the slope of a line that is perpendicular to this line, we use the fact that the product of the slopes of two perpendicular lines is -1. So the slope of the perpendicular line is the negative reciprocal of -1, which is 1.
Therefore, the answer is B. m = 2.
11 answers