7.A turntable reaches an angular speed of 33.3 rpm, in 2.1 s, starting from rest.

Question

(a) Assuming the angular acceleration is constant, what is its magnitude?

b How many revolutions does the turntable make during this time interval?

Answer 1

V = 33.3rev/1min = 33.3rev/60s - 0.555rev/s.

a. a = (Vf - Vi) / t,
a = (0.555 - 0) / 2.1 = 0.264rev/s^2.

b. rev = 0.555rev/s * 2.1s = 1.17.

Answer 2

post

Answer 3

b) is incorrect above. You need to divide by 2 because the answer is the average velocity multiplied by time.

The correct answer is 0.585 revolutions.