7) A population of ants is growing at a rate of 8% a year. If there are 160 ants in the initial population, find

Question

the number of ants after 6 years.

Answer 1

8% + 100% = 108% = 108 / 100 = 1.08

The n-th term of a geometric sequence with initial value a1 and common ratio r is given by:

an = a1 ∙ r ⁿ⁻¹

In tis case :

a1 = 160

r = 1.08

Need to notice that term two is after one year, so term 7 will be after 6 years.

n = 7

so:

a6 = a1 ∙ r⁷⁻¹

a6 = 160 ∙ r⁶

a6 = 160 ∙ 1.08⁶

a6 = 160 ∙ 1.586874322944

a6 = 253.89989167104

The number of ants after 6 years will be 253.

Answer 2

Why plusing this 100 % and rate of 8%