heat lost by tungsten + heat gained by water = 0
Is that hint good enough?
7. A 100g mass of tungsten at 100 degrees C is placed in 200 mL of water at 20 degrees C. The mixture reaches equilibrium at 21.6 degrees C. Calculate the specific heat of tungsten.
Ok, I tried working it out but I got
q= 100g x 4.186 j/g*degrees C * (21.6 degrees C- 20.0 degrees C) which equals to 1.6.
So q= 100g * 4.186 j/g*deg C * 1.6
I got a very high number. I am stuck what do I do?
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From what I am learning right now you should be using kilos, that would definitely affect your answer.
2 answers