Asked by pickles
7
6
A
10
432
B
NON
x
-7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7
CON
A
What is the midpoint of line segment AB?
Enter your answer as a decimal if necessary.
6
A
10
432
B
NON
x
-7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7
CON
A
What is the midpoint of line segment AB?
Enter your answer as a decimal if necessary.
Answers
There are no human answers yet.
Answered by
GPT-4o mini
The coordinates of points A and B are given as follows:
- Point A: \((7, 6)\)
- Point B: \((10, 432)\)
To find the midpoint \( M \) of the line segment \( AB \), we use the midpoint formula:
\[
M = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)
\]
Substituting the coordinates of points A and B into the formula:
\[
M = \left( \frac{7 + 10}{2}, \frac{6 + 432}{2} \right)
\]
Calculating the x-coordinate of the midpoint:
\[
\frac{7 + 10}{2} = \frac{17}{2} = 8.5
\]
Calculating the y-coordinate of the midpoint:
\[
\frac{6 + 432}{2} = \frac{438}{2} = 219
\]
Thus, the midpoint \( M \) of line segment \( AB \) is:
\[
M = (8.5, 219)
\]
In summary, the midpoint of line segment AB is \( (8.5, 219) \).
- Point A: \((7, 6)\)
- Point B: \((10, 432)\)
To find the midpoint \( M \) of the line segment \( AB \), we use the midpoint formula:
\[
M = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)
\]
Substituting the coordinates of points A and B into the formula:
\[
M = \left( \frac{7 + 10}{2}, \frac{6 + 432}{2} \right)
\]
Calculating the x-coordinate of the midpoint:
\[
\frac{7 + 10}{2} = \frac{17}{2} = 8.5
\]
Calculating the y-coordinate of the midpoint:
\[
\frac{6 + 432}{2} = \frac{438}{2} = 219
\]
Thus, the midpoint \( M \) of line segment \( AB \) is:
\[
M = (8.5, 219)
\]
In summary, the midpoint of line segment AB is \( (8.5, 219) \).
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