7 5.8×10^7

bacteria are measured to be in a dirt sample that weighs 11 gram. Use scientific notation to express the number of bacteria that would be in a sample weighing 1818 grams

1 answer

To find the number of bacteria in a sample weighing 1818 grams, we can set up a ratio based on the known quantity of bacteria in the 11-gram sample.

Given:

  • Number of bacteria in 11 grams = \( 5.8 \times 10^7 \)
  • Weight of sample = 11 grams

First, we can calculate the number of bacteria per gram:

\[ \text{Bacteria per gram} = \frac{5.8 \times 10^7 \text{ bacteria}}{11 \text{ grams}} = \frac{5.8}{11} \times 10^7 \text{ bacteria/gram} \]

Calculating \( \frac{5.8}{11} \):

\[ \frac{5.8}{11} \approx 0.5273 \text{ (to four decimal places)} \]

Now, we can express this in scientific notation:

\[ 0.5273 \approx 5.273 \times 10^{-1} \]

Thus, the number of bacteria per gram is:

\[ 5.273 \times 10^{-1} \times 10^7 = 5.273 \times 10^{6} \text{ bacteria/gram} \]

Now, we can apply this to the 1818-gram sample:

\[ \text{Number of bacteria in 1818 grams} = 5.273 \times 10^6 \text{ bacteria/gram} \times 1818 \text{ grams} \]

Calculating \( 5.273 \times 1818 \):

\[ 5.273 \times 1818 \approx 9602.274 \]

Now we express this in scientific notation.

\[ 9602.274 \approx 9.602274 \times 10^3 \]

Now we need to convert this to an appropriate form. Since we are multiplying by \( 10^6 \), we can combine:

\[ 9.602274 \times 10^3 \times 10^6 = 9.602274 \times 10^{9} \]

Therefore, rounding to three significant figures, we can express the final number of bacteria in a sample weighing 1818 grams as:

\[ \approx 9.60 \times 10^9 \]

So, the final answer is:

\[ 9.60 \times 10^9 \text{ bacteria} \]