We will solve these two inequalities separately:
1) -7 ≥ -3x + 8
Subtract 8 from both sides:
-15 ≥ -3x
Divide by -3 (since dividing by a negative number switches the inequality sign):
5 ≤ x
2) -3x + 8 > -19
Subtract 8 from both sides:
-3x > -27
Divide by -3:
x < 9
Therefore, the solution to the system of inequalities is:
5 ≤ x < 9
−7≥−3x+8and
−3x+8>−19
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