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7.0 mL of 0.5 M acetic acid contains 0.0035 moles of acetic acid. how many moles of sodium bicarbonate are needed to react with 0.0035 moles of acetic acid?

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Balance the equation.

2 H-CH3COO + 2NaHCO3 >> 2NaCH3COO +CO2 +2H2O

It appears the same number of moles.

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