To simplify the expression \(6xy - 3x - 8y + 4\), we can rearrange and group the terms: 1. Group like terms: \[ 6xy - 3x - 8y + 4 \] 2. There are no like terms to combine directly, but you can factor out common factors if needed. For example, you can factor out \( -1 \) from the last two terms: \[ 6xy - 3x - (8y - 4) \] or keep it as is. 3. If you want to organize the expression further or if you have any specific requirement (like factoring or rearranging), please let me know! In its current form, the expression \(6xy - 3x - 8y + 4\) is already simplified, but if factoring or rearranging is needed let me know!

To factor the expression \(6xy - 3x - 8y + 4\), follow these steps: 1. **Group the terms**: Group the first two terms together and the last two terms together: \[ (6xy - 3x) + (-8y + 4) \] 2. **Factor out the common factors from each group**: - From the first group \(6xy - 3x\), you can factor out \(3x\): \[ 3x(2y - 1) \] - From the second group \(-8y + 4\), you can factor out \(-4\): \[ -4(2y - 1) \] So now we have: \[ 3x(2y - 1) - 4(2y - 1) \] 3. **Factor out the common binomial factor**: Now, you can see that both groups contain the common factor \((2y - 1)\): \[ (2y - 1)(3x - 4) \] Thus, the factored form of the expression \(6xy - 3x - 8y + 4\) is: \[ (2y - 1)(3x - 4) \]

6xy−3x−8y+4

To simplify the expression \(6xy - 3x - 8y + 4\), we can rearrange and group the terms:

Group like terms: \[ 6xy - 3x - 8y + 4 \]
There are no like terms to combine directly, but you can factor out common factors if needed. For example, you can factor out \( -1 \) from the last two terms: \[ 6xy - 3x - (8y - 4) \] or keep it as is.
If you want to organize the expression further or if you have any specific requirement (like factoring or rearranging), please let me know!

In its current form, the expression \(6xy - 3x - 8y + 4\) is already simplified, but if factoring or rearranging is needed let me know!

Factor 6xy−3x−8y+4

To factor the expression \(6xy - 3x - 8y + 4\), follow these steps:

Group the terms: Group the first two terms together and the last two terms together: \[ (6xy - 3x) + (-8y + 4) \]
Factor out the common factors from each group:
- From the first group \(6xy - 3x\), you can factor out \(3x\): \[ 3x(2y - 1) \]
- From the second group \(-8y + 4\), you can factor out \(-4\): \[ -4(2y - 1) \]
So now we have: \[ 3x(2y - 1) - 4(2y - 1) \]
Factor out the common binomial factor: Now, you can see that both groups contain the common factor \((2y - 1)\): \[ (2y - 1)(3x - 4) \]

Thus, the factored form of the expression \(6xy - 3x - 8y + 4\) is: \[ (2y - 1)(3x - 4) \]