The correct answer is -2.
To expand -3(2x - 1)(x + __), we first find the missing term in the second set of parentheses by dividing -6 by -3, which gives us positive 2.
So, -3(2x - 1)(x + 2) = -3(2x^2 + 4x - x - 2) = -3(2x^2 + 3x - 2) = -6x² + 15x - 6
–6x² + 15x – 6 = –3(2x – 1)(x + __)
2
–2
–3
1 answer