regardless of the base, log(1) = 0,
because x^0 = 1
so, what you have is
6x-12 = 0
x = 2
try writing log_x(n) for log of n (base x). The underscore indicates the base.
6x-12=log(x)1
that is base x
I know the answer is 2 but not sure how to do
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