Asked by Angel007
(-6v^2 - 4 + 9v +v^3)/ (v - 4)i am just a little lost can someone explain this to me. thanks.
Arrange the polonomial in descending order...
v^3-6v^2 +9v -4
Then divide.
v-4 !v^3-6v^2 +9v -4
The first term is v^2, so v^2*(v-4) is
v^3-4v^2
subtracting that from the polonomial gives
v-4 ! -2v^2+9v-4
so dividing one gets -2v, then multiplying by v-4 gives
-2v(v-4)=-2v^2+8v, and subtracting that frm -2v^2+9v-4 gives
v-4 ! v-4, and dividing gives 1.
so the answer is v^2 -2v +1
check my thinking.
Arrange the polonomial in descending order...
v^3-6v^2 +9v -4
Then divide.
v-4 !v^3-6v^2 +9v -4
The first term is v^2, so v^2*(v-4) is
v^3-4v^2
subtracting that from the polonomial gives
v-4 ! -2v^2+9v-4
so dividing one gets -2v, then multiplying by v-4 gives
-2v(v-4)=-2v^2+8v, and subtracting that frm -2v^2+9v-4 gives
v-4 ! v-4, and dividing gives 1.
so the answer is v^2 -2v +1
check my thinking.
Answers
There are no human answers yet.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.