6sin(2x)+3=0

Question

How do you find the smallest value of x in the interval 0≤x≤π for which y=0?

My work so far:
6sin(2x)=-3
sin(2x)=-1/2

The answer should be 7π/12, or 1.83

Thanks in advance!

Answer 1

sin π/6 = 1/2

since sine is negative is QIII and QIV, we have

2x = 7π/6 or 11π/6

that should help.