This is a limiting reagent (LR) problem. You know that because amounts are given for BOTH reactants.
6Na + Fe2O3 ==> 3Na2O + 2Fe
1. mols Na = grams/molar mass
2. mols Fe2O3 = grams/molar mass
3a. Using the coefficients in the balanced equation, convert mols Na to mols of the product, Fe.
3b. Do the same for mols Fe2O3 to mols Fe.
3c. It is likely that the values for mols Fe from 3a and 3b will not agree which means one of them is not right. The correct value in LR problems is ALWAYS the smaller value and the reagent producing that value is the LR.
4. Now convert mols Fe to g. g = mols x molar mass.
6Na+Fe2O3=3Na2O+2Fe
if Interact 100g of Na with 100g of Fe2O3,Calculate:
- The resulting mass of iron?
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